9x^2-10x-12=0

Solution for 9x^2-10x-12=0 equation:

9x^2-10x-12=0

a = 9; b = -10; c = -12;
Δ = b2-4ac
Δ = -102-4·9·(-12)
Δ = 532
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{532}=\sqrt{4*133}=\sqrt{4}*\sqrt{133}=2\sqrt{133}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{133}}{2*9}=\frac{10-2\sqrt{133}}{18}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{133}}{2*9}=\frac{10+2\sqrt{133}}{18}
$